Check Armstrong Number
Check whether a number is an Armstrong number (sum of digits^number-of-digits equals the number).
IntermediateTopic: Module 2: Conditional Programs
Java Check Armstrong Number Program
This program helps you to learn the fundamental structure and syntax of Java programming.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number: ");
int n = sc.nextInt();
int temp = n;
int digits = 0;
while (temp != 0) {
digits++;
temp /= 10;
}
temp = n;
int sum = 0;
while (temp != 0) {
int d = temp % 10;
int pow = 1;
for (int i = 0; i < digits; i++) {
pow *= d;
}
sum += pow;
temp /= 10;
}
if (sum == n) {
System.out.println(n + " is an Armstrong Number");
} else {
System.out.println(n + " is not an Armstrong Number");
}
sc.close();
}
}Output
Enter a number: 153 153 is an Armstrong Number
Understanding Check Armstrong Number
We raise each digit to the power of the total digits and add them; if the sum equals the original number, it is Armstrong.
Note: To write and run Java programs, you need to set up the local environment on your computer. Refer to the complete article Setting up Java Development Environment. If you do not want to set up the local environment on your computer, you can also use online IDE to write and run your Java programs.