Logic Building/Phase 2 - Level 2: Number-based Looping Logic/Program

Abundant Number Check

Check if sum of proper divisors exceeds the number.

Logic BuildingIntermediate

Logic Building

# Take number
num = int(input("Enter a number: "))

# Find sum of proper divisors
divisor_sum = 0
for i in range(1, num):
    if num % i == 0:
        divisor_sum += i

# Check abundant
if divisor_sum > num:
    print("Abundant number")
else:
    print("Not an abundant number")

Output

Enter a number: 12
Abundant number

Sum of proper divisors > number.

Key Concepts:

Find all proper divisors
Sum them
Compare with number

Harshad Number Check